【人気ダウンロード！】 p(x)=3x find the zero of polynomial 284495-P(x)=3x find the zero of polynomial
Solution Let p(x) = x 2 – √3x 40 = x 2 – 5x – 8x 40 = x(x – 5) – 8(x – 5) = (x(i) Graph y = p(x) does not cut the xaxis at any point, so the given polynomial has no zero (ii) Graph y = p(x) cuts the xaxis at one point, so the given polynomial has one zero (iii) Graph y = p(x) cuts the xaxis at three points, so the given polynomial has three zeroes0 votes 1 answer If one zero of the polynomial 3x^28x2k1 is seven times the other, find the value of k
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P(x)=3x find the zero of polynomial
P(x)=3x find the zero of polynomial-If P(X) is a polynomial in x, the highest power of x in P(x) is called the degree of the polynomial P(x) Ex The degree of polynomial P(X) = 2x 3 5x 27 is 3 because the degree of a polynomial is the highest power of polynomial Zero of polynomial If the value of P(x) at x = K is zero then K is called a zero of the polynomial P(x)X^23x10 Find the zeros of the quadratic polynomial n23x10, and verify the relation between the zeros and its coefficients Maths Class 10th Polynomials question if x and b are the roots of the polynomial f(x)=x2 please answer quickly
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Ans x=1,1,2 A real number k is a zero of a polynomial p(x), if p(k) =0 It is nothing but the roots of the polynomial function x^32x^2x2=0 //TrickThe sum ofIf P(x) is a polynomial in x and k is any real number, then the value of P(k) at x = k is denoted by P(k) is found by replacing x by k in P(x) Example 2 In the polynomial x 2 – 3x 2, Replacing x by 1 gives, P(1) = 1 – 3 2 = 0 Similarly, replacing x by 2 gives, P(2) = 462 = 0 For a polynomial P(x), real number kWe are given the following polynomial We have to find the zeroes of the polynomial A root or a zero of a polynomial are the value of x that cause the polynomial p(x) = 0 Thus, equating the given polynomial to 0, we get By hit and trial method we get that x = 2 is a root of the given polynomial Thus, is a factor of the given polynomial
P(x)= 3x2 3x2 =0 3x=02 3x= 2 x= 2/3 therefore p(2/3) = 3x2 p(2/3)= 3x2/32 p(2/3=0 therefore p(x)=0 so, 2/3 is the zero of the polynomial =3x2 (2) solution p(x)=2x5 2x5=0 2x=05 2x= 5 x= 5/2 p(5/2)= 2x 5/2 5 p(5/2)= 0 therefore p(x)= 0so, x is the zero of the polynomial= 2x5Transcript Example 4 Find a zero of the polynomial p(x) = 2x 1 Putting p(x) = 0 2x 1 = 0 2x = 1 x = 1/2 So, 1/2Find all zeros of the polynomial P(x) = x^3 3x^2 10x 24 knowing that x = 2 is a zero of the polynomial
Any polynomial that can be defined by an equation of the form p(x) = ax b where a and b are real numbers and a (not equal to sign) 0 is considered to be linear For example, p(x)=3x7 For example, p(x)=3x7Click here 👆 to get an answer to your question ️ find the zero of the polynomial p(x)=3x2 7swapna7 7swapna7 Math Secondary School Find the zero of the polynomial p(x)=3x2 2 See answers kkpanditpautra kkpanditpautra Answer Stepbystep explanation p(2/3)=3×2/32 22=0If the rational number x = b c x = b c is a zero of the n n th degree polynomial, P (x) = sxn ⋯t P ( x) = s x n ⋯ t where all the coefficients are integers then b b will be a factor of t t and c c will be a factor of s s Note that in order for this theorem to work then the zero must be reduced to lowest terms
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Example 2 Find the zero of the polynomial in each of the following cases (i) p(x) = x 5 (ii) p(x) = 2x 5 (iii) p(x) = 3x – 2 Sol To find the zero of a polynomial p(x) means to solve the polynomial equation p(x) = 0 (i) For the zero of polynomial p(x) = x 5 p(x) = 0 ⇒ x 5 = 0 ⇒ x = –5 ∴ x = –5 is a zero of the polynomialFind the zeros of the polynomial f(x)=x^312x^239x28,if it is given that the zeros are in AP asked Jan 29, 18 in Mathematics by sforrest072 ( 128k points) polynomialsX^23x10 Find the zeros of the quadratic polynomial n23x10, and verify the relation between the zeros and its coefficients Maths Class 10th Polynomials question if x and b are the roots of the polynomial f(x)=x2 please answer quickly
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(i) Graph y = p(x) does not cut the xaxis at any point, so the given polynomial has no zero (ii) Graph y = p(x) cuts the xaxis at one point, so the given polynomial has one zero (iii) Graph y = p(x) cuts the xaxis at three points, so the given polynomial has three zeroesAny polynomial that can be defined by an equation of the form p(x) = ax b where a and b are real numbers and a (not equal to sign) 0 is considered to be linear For example, p(x)=3x7Click here👆to get an answer to your question ️ If 2 is a zero of the polynomial p(x) = 2x^2 3x 7a , find the value of a
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Transcript Example 3 Find the zeroes of the polynomial x2 3 and verify the relationship between the zeroes and the coefficients Let p(x) = x2 3 Zero of the polynomial is the value of x where p(x) = 0 Putting p(x) = 0 x2 3 = 0 (x)2 ( 3)2 = 0 Using a2 b2 = (a b)(a b) (x 3)(x 3) = 0 So x = 3 , 3 Therefore, = 3 & = 3 are zeroes of the polynomial We can write p(x) = x2 3 = x2 0 3 = 1x2For these cases, we first equate the polynomial function with zero and form an equation Then we solve the equation The roots of an equation are the roots of a function Suppose the given polynomial is f(x)=2x1 and we have to find the zero of the polynomial Now equating the function with zero we get, 2x1=0 or, 2x=1 or, x= \frac{1}{2}Let P (x) ax 3, bx 2 cx d Now, P (3) = 3 (3) 3 (– 5) (3) 2 (11) (3) (3) = 81 45 33 3 = 0 and Therefore, the given values 3, 1 and are the zeroes of 3x 3 – 5x 2 – 11x – 3 Verification of relationship between zeroes and the coefficients the zeroes of 3x 3 – 5x 2 – 11x – 3 2259 Views
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Now, for zeroes of given polynomial, put p(x) = 0 ∴ (x – 5) (x – 8) = 0 ⇒ x = 5 or x = 8 Hence, other zero is 8 Question 6 Simplify Solution Question 7 If one zero of the polynomial x 2 – √3x 40 is 5, which is the other zero ?Find the zeroes of the following quadratic polynomials and verify the relationship between the zeroes and the coefficients (i) x 2 − 2 x − 8 (i i) 4 s 2 − 4 s 1 (i i i) 6 x 2 − 3 − 7 x (i v) 4 u 2 8 u (v) t 2 − 1 5 (v i) 3 x 2 − x − 4If x = 0 and x = 1 are the roots of the polynomial f(x) = 2x^3 − 3x^2 ax b, find the value of a and b asked Aug 7, 18 in Mathematics by Sonu khan ( 356k points) factorization of polynomials
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